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Solved Questions Paper-2 UGC-NET Computer Science January 2017

1.Consider a sequence F00 defined as:

Then what shall be the set of values of the sequence F00?
A.(1, 110, 1200)
B.(1, 110, 600, 1200)
C.(1, 2, 55, 110, 600, 1200)
D.(1, 55, 110, 600, 1200)
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Explanation
2.Match the following:
List-I List-II
a. Absurd i. Clearly impossible being contrary to some evident truth.
b. Ambiguous ii. Capable of more than one interpretation or meaning.
c. Axiom iii. An assertion that is accepted and used without a proof.
d. Conjecture iv. An opinion Preferably based on some experience or wisdom.

Codes: a b c d
A. i ii iii iv
B.i iii iv ii
C.ii iii iv i
D.ii i iii iv
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3.The functions mapping R into R are defined as:
f(x) = x3-4x, g(x)=1/(x2+1) and h(x)=x4 Then find the value of the following composite functions:
hog(x) and hogof(x)
A.(A) (x2+1)4 and [(x3-4x)2+1]4
B.(x2+1)4 and [(x3-4x)2+1]-4
C.(x2+1)-4 and [(x3-4x)2+1]4
D.(x2+1)?4 and [(x3-4x)2+1]-4
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4.How many multiples of 6 are there between the following pairs of numbers? 0 and 100 and -6 and 34
A.16 and 6
B.17 and 6
C.17 and 7
D.16 and 7
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5.Consider a Hamiltonian Graph G with no loops or parallel edges and with |V(G)|=n?3. Then which of the following is true?
A.deg(v) ? n/2 for each vertex v.
B.|E(G)| ? 1/2(n-1)(n-2)+2
C.deg(v)+deg(w) ? n whenever v and w are not connected by an edge.
D.All of the above
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6.In propositional logic if (P?Q)?(R?S) and (P?R) are two premises such that

Y is the premise:
A.P?R
B.P?S
C.Q?R
D.Q?S
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7.ECL is the fastest of all logic families. High Speed in ECL is possible because transistors are used in difference amplifier configuration, in which they are never driven into ...............
A.Race condition
B.Saturation
C.Delay
D.High impedance
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8.A binary 3-bit down counter uses J-K flip-flops, FFi with inputs Ji, Ki and outputs Qi, i=0,1,2 respectively. The minimized expression for the input from following, is
I. J0=K0=0
II. J0=K0=1
III. J1=K1=Q0
IV. J1=K1=Q'0
V. J2=K2=Q1Q0
Vl. J2=K2=Q'1Q'0
A. I, III, V
B.I, IV, VI
C.II, III, V
D.II, IV, VI
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9.Convert the octal number 0.4051 into its equivalent decimal number.
A.0.5100098
B.0.2096
C.0.52
D.0.4192
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Explanation
10.The hexadecimal equivalent of the octal number 2357 is:
A.2EE
B.2FF
C.4EF
D.4FE
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Author Does Not claim of any answer these answers are as per expert opinion

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